In the diagram find out the current thro...

In the diagram find out the current through `2 Omega` `(R_(3))` :

Verified by Experts

The correct Answer is:

`9//2`

`"Let"V_(A)=0" so "V_(B)=0`
`V_(C)=3"volt "V_D=-6"volt"`
`"So",V_(C)-V_(D)=IR`
`9=Ixx2" "I=(9)/(2)"Amp."`

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