Home
Class 12
PHYSICS
An N-P-N transistor is connécted in comm...

An N-P-N transistor is connécted in common emitter contiguration in which collector supply is 9V and the voltage drop across the load resistance of `1000Omega` connected in the collector circuit is 1V. If current amplification factor is (25/26), then the base current is

Text Solution

Verified by Experts

The circuit arrangement is shown in figure. Collector currnet `I_(C)=("Voltage drop across R"_(1))/(R_(1))`
`=(1)/(1000)=10^-3"amp"`
Now, vc `V_(CE)=9-1=8"volt"`
`=(l_(C))/(l_(B))" "(25)/(26)=(10^(-3))/(I_B)`
Current gain `beta= or `
`therefore I_(B)=1.04xx10^(-3)amp`
Promotional Banner

Similar Questions

Explore conceptually related problems

An n - p- n transistor is connected in common - emitter configuraration in which collector supply is 8 V and the voltage drop across the load resistance of 800 Omega connected in the collector circuit is 0.8 V . If current amplification factor is 25 , determine collector - emitter voltage and base current . If the internal resistance of the transistor is 200 Omega , calculate the voltage gain and the power gain.

A transistor is connected in common emmitter (CE) configuration. The collector supply is 8V and the voltage deop across a resistor of 800 Omega in the collector circuit is 0.8 V . If the current gain factor (alpha) is 0.96 , then the change in base current is

A transistor is connected in a common emitter configuration. The collector supply is 8 V and the voltage drop across a resistor of 800 Omega in the collector circuit is 0.5 V. If the current gain factor (alpha) is 0.96 , Find the base current.

A transistor is connected in common base configuration, the collector supply is 8V and the voltage drop across a resistor of 800 Omega in the collector circuit is 0.5V. If the current gain alpha is 0.96, then the base current is

A n-p-n transisitor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across it is 0.8 V . If the current amplification factor is 0.96 and the input resistance of the circuits is 192 Omega , the voltage gain and the power gain of the amplifier will respectively be

A npn transistor is connectedin CEC in which collector voltage drop across load resistance (800 ohm) connected to collector circuit is 0.8V The collector current is

In a transitor (Beta = 50) , the voltage across 5 kOmega load resistance in collector circuit is 5V . The base current is

For a common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2 kOmega is 2 V. Suppose the current amplification factor of the transistor is 100, the base current if base resistance is 1 k Omega is

A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and beta is 50, the base current if R_C is 2 kOmega is

An NPN transistor is used in common emitter configuration as an amplifier with 1k Omega load resistance. Signal voltage of 10 mV is applied a across the base-emitter. This produces a 3 mA change in the collector current and 15 mu A change in the base currect of the amplifier. The input resistance and voltage gain are :