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Light is incident on a polarizer with in...

Light is incident on a polarizer with intensity `I_0`. A second prism called analyzer is kept at a angle of `15^@`, from the first polarizer then the intensity of final emergent light will be

Text Solution

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`I=(I_(0))/(2)cos^(2)(15^(@))`
`I=(I_(0))/(4).2cos^(2)(15^(@))` `I=(I_(0))/(4)[1+cos(30^(@))]`
`I=(I_(0))/(4)[1+(sqrt3)/(2)]`
`I=(I_(0))/(4)[2+sqrt3]`
`I=0.46I_(0)d`
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