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Which of the following option is valid f...

Which of the following option is valid for zero reaction?

A

`t_(1//2)=(3)/(2)t_(1//4)`

B

`t_(1//2)=(4)/(3)t_(1//4)`

C

`t_(1//2)=2t_(1//4)`

D

`t_(1//4)=(t_(1//2))^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the valid option for a zero-order reaction, we need to derive the expressions for the half-life (t₁/₂) and the quarter-life (t₁/₄) of a zero-order reaction and then find their ratio. ### Step-by-Step Solution: 1. **Understanding Zero-Order Reaction**: - In a zero-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. - The general form of the rate equation for a zero-order reaction is: \[ \text{Rate} = k \] - The concentration of the reactant (A) at time t can be expressed as: \[ [A] = [A_0] - kt \] where [A₀] is the initial concentration and k is the rate constant. 2. **Deriving the Half-Life (t₁/₂)**: - The half-life is the time required for the concentration of the reactant to reduce to half of its initial concentration. - Setting [A] = [A₀]/2 in the equation: \[ \frac{[A_0]}{2} = [A_0] - kt_{1/2} \] - Rearranging gives: \[ kt_{1/2} = [A_0] - \frac{[A_0]}{2} = \frac{[A_0]}{2} \] - Therefore, we can express t₁/₂ as: \[ t_{1/2} = \frac{[A_0]}{2k} \] 3. **Deriving the Quarter-Life (t₁/₄)**: - The quarter-life is the time required for the concentration of the reactant to reduce to one-fourth of its initial concentration. - Setting [A] = [A₀]/4 in the equation: \[ \frac{[A_0]}{4} = [A_0] - kt_{1/4} \] - Rearranging gives: \[ kt_{1/4} = [A_0] - \frac{[A_0]}{4} = \frac{3[A_0]}{4} \] - Therefore, we can express t₁/₄ as: \[ t_{1/4} = \frac{3[A_0]}{4k} \] 4. **Finding the Ratio of t₁/₂ to t₁/₄**: - Now we can find the ratio of t₁/₂ to t₁/₄: \[ \frac{t_{1/2}}{t_{1/4}} = \frac{\frac{[A_0]}{2k}}{\frac{3[A_0]}{4k}} = \frac{[A_0]}{2k} \cdot \frac{4k}{3[A_0]} = \frac{4}{6} = \frac{2}{3} \] 5. **Conclusion**: - The ratio of the half-life to the quarter-life for a zero-order reaction is \( \frac{2}{3} \). - Therefore, we check the options provided in the question to find the one that corresponds to this ratio. ### Final Answer: - The correct option is **C**, as it represents the valid ratio for a zero-order reaction.

To solve the question regarding the valid option for a zero-order reaction, we need to derive the expressions for the half-life (t₁/₂) and the quarter-life (t₁/₄) of a zero-order reaction and then find their ratio. ### Step-by-Step Solution: 1. **Understanding Zero-Order Reaction**: - In a zero-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. - The general form of the rate equation for a zero-order reaction is: \[ ...
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