`CH_(3)-CH=CH-CH=N-CH_(3)overset(LiAlH_(4))to` What is final product

Options

A. `CH_(3)-CH_(2)-CH_(2)-CH_2-NH-CH_(3)`
B. `CH_3-CH=CH-CH2-NH-CH_3`
C. `CH_3-CH_2_CH_2-CH-N-CH_3`
D. `CH_3-CH=CH-OH_2-OH`

Explanation

To solve the question regarding the reaction of the compound \( CH_3-CH=CH-CH=N-CH_3 \) with \( LiAlH_4 \), we will go through the following steps:

### Step-by-Step Solution:

1. **Identify the Functional Groups**: The compound \( CH_3-CH=CH-CH=N-CH_3 \) contains an alkene (the \( CH=CH \) part) and an imine (the \( CH=N \) part).

2. **Understand the Reactant**: Lithium aluminum hydride (\( LiAlH_4 \)) is a strong reducing agent that primarily reduces carbonyls and imines. It is important to note that \( LiAlH_4 \) will preferentially react with the imine over the alkene.

3. **Reduction of the Imine**: When \( LiAlH_4 \) is added to the compound, it will donate a hydride ion (\( H^- \)) to the imine group \( CH=N \). This will convert the imine into an amine. The reaction can be represented as:
\[ CH_3-CH=CH-CH=N-CH_3 + LiAlH_4 \rightarrow CH_3-CH=CH-CH_2-NH_2-CH_3 \]

4. **Final Product Structure**: After the reduction, the double bond between the carbon atoms remains intact, while the imine is reduced to an amine. The final product will have the structure:
\[ CH_3-CH=CH-CH_2-NH_2-CH_3 \]

5. **Identify the Correct Option**: Based on the final structure obtained, we can compare it with the provided options to determine the correct answer.

### Final Answer:
The final product after the reaction of \( CH_3-CH=CH-CH=N-CH_3 \) with \( LiAlH_4 \) is \( CH_3-CH=CH-CH_2-NH_2-CH_3 \).