Which of the following at least one lone pair in all of its halide.

Options

A. Xe
B. Se
C. Cl
D. N

Answer

To solve the question "Which of the following has at least one lone pair in all of its halides?" we will analyze the halides of each given element: Xenon, Selenium, Chlorine, and Phosphorus.

### Step-by-Step Solution:

1. **Identify the Elements and Their Halides**:
- **Xenon (Xe)**: Common halides include XeF2, XeF4, XeOF4, and XeO2F2.
- **Selenium (Se)**: Common halides include SeCl2 and SeCl6.
- **Chlorine (Cl)**: Chlorine itself is a halogen and does not form halides with other halogens.
- **Phosphorus (P)**: Common halides include PCl3 and PCl5.

2. **Analyze Xenon Halides**:
- **XeF2**:
- Valence electrons = 8
- Bond pairs = 2 (with 2 fluorine atoms)
- Lone pairs = 8 - 2 = 6 (3 lone pairs)
- **XeF4**:
- Valence electrons = 8
- Bond pairs = 4 (with 4 fluorine atoms)
- Lone pairs = 8 - 4 = 4 (2 lone pairs)
- **XeOF4**:
- Valence electrons = 8
- Bond pairs = 5 (4 with fluorine and 1 with oxygen)
- Lone pairs = 8 - 5 = 3 (1 lone pair)
- **XeO2F2**:
- Valence electrons = 8
- Bond pairs = 4 (2 with oxygen and 2 with fluorine)
- Lone pairs = 8 - 4 = 4 (1 lone pair)
- **Conclusion for Xenon**: All halides have at least one lone pair.

3. **Analyze Selenium Halides**:
- **SeCl2**:
- Valence electrons = 6
- Bond pairs = 2 (with 2 chlorine atoms)
- Lone pairs = 6 - 2 = 4 (2 lone pairs)
- **SeCl6**:
- Valence electrons = 6
- Bond pairs = 6 (with 6 chlorine atoms)
- Lone pairs = 6 - 6 = 0 (0 lone pairs)
- **Conclusion for Selenium**: SeCl6 has no lone pairs, so it does not satisfy the condition.

4. **Analyze Chlorine Halides**:
- Chlorine does not form halides with other halogens (it is itself a halogen).
- **Conclusion for Chlorine**: No lone pairs can be analyzed as it does not form halides.

5. **Analyze Phosphorus Halides**:
- **PCl3**:
- Valence electrons = 5
- Bond pairs = 3 (with 3 chlorine atoms)
- Lone pairs = 5 - 3 = 2 (1 lone pair)
- **PCl5**:
- Valence electrons = 5
- Bond pairs = 5 (with 5 chlorine atoms)
- Lone pairs = 5 - 5 = 0 (0 lone pairs)
- **Conclusion for Phosphorus**: PCl5 has no lone pairs, so it does not satisfy the condition.

6. **Final Conclusion**:
- The only element that has at least one lone pair in all of its halides is **Xenon (Xe)**.

### Answer:
The correct option is **Xenon (Option A)**.