When `CH_(3)COOCH_(3)+HCl` is titrated with `NaOH` then at neutral point the colour of phenopthalein becomes colourless from pink due to:

Options

A. due to formation of `CH_(3)OH`
B. due to formation of `CH_(3)COOH` which act as a weak acid.
C. Phenophalein vaporizes.
D. due to presence of HCI

Explanation

To solve the question, we need to analyze the chemical reactions occurring during the titration of methyl acetate (CH₃COOCH₃) with hydrochloric acid (HCl) and sodium hydroxide (NaOH) in the presence of phenolphthalein as an indicator.

### Step-by-Step Solution:

1. **Identify the Components**:
- We have methyl acetate (CH₃COOCH₃), hydrochloric acid (HCl), and sodium hydroxide (NaOH).
- Phenolphthalein is used as an indicator, which is pink in basic solutions and colorless in acidic solutions.

2. **Reaction of Methyl Acetate with HCl**:
- When methyl acetate is mixed with HCl, it undergoes hydrolysis to form acetic acid (CH₃COOH) and methanol (CH₃OH):
\[ CH₃COOCH₃ + H₂O \xrightarrow{HCl} CH₃COOH + CH₃OH \]

3. **Titration with NaOH**:
- The acetic acid formed is a weak acid. When NaOH is added to the solution, it reacts with acetic acid to form sodium acetate (CH₃COONa) and water:
\[ CH₃COOH + NaOH \rightarrow CH₃COONa + H₂O \]

4. **Effect on Phenolphthalein**:
- Initially, the solution is basic due to the presence of NaOH, and phenolphthalein shows a pink color.
- As acetic acid is formed and reacts with NaOH, the solution approaches neutrality. At the neutral point, the solution becomes less basic, and the phenolphthalein indicator changes from pink to colorless.

5. **Conclusion**:
- The color change of phenolphthalein from pink to colorless at the neutral point is due to the formation of acetic acid (CH₃COOH), which is a weak acid.

### Final Answer:
The color of phenolphthalein becomes colorless from pink due to the formation of CH₃COOH, which acts as a weak acid.