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A man (mass =50 kg) is in an elevtor wit...

A man (mass =50 kg) is in an elevtor with is moving with acceleration `0.49 m//s^(2)` upwards. Find normal reaction exerted by man on floor of the elevator.

A

`214.5N`

B

`314.5N`

C

`414.5N`

D

`514.5N`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the normal reaction exerted by the man on the floor of the elevator. Here’s the step-by-step solution: ### Step 1: Identify the forces acting on the man When the elevator is moving upwards with an acceleration, two main forces act on the man: 1. The weight of the man (downwards), which is given by \( W = mg \), where \( m \) is the mass of the man and \( g \) is the acceleration due to gravity. 2. The normal force (upwards), which we will denote as \( N \). ### Step 2: Write down the expressions for the forces - The weight of the man can be calculated as: \[ W = mg \] Given that \( m = 50 \, \text{kg} \) and \( g \approx 9.8 \, \text{m/s}^2 \): \[ W = 50 \times 9.8 = 490 \, \text{N} \] ### Step 3: Apply Newton's second law Since the elevator is accelerating upwards, we can apply Newton's second law in the vertical direction: \[ N - W = ma \] Where: - \( N \) is the normal force, - \( W \) is the weight, - \( m \) is the mass of the man, - \( a \) is the acceleration of the elevator. ### Step 4: Substitute the known values into the equation We know: - \( W = 490 \, \text{N} \) - \( m = 50 \, \text{kg} \) - \( a = 0.49 \, \text{m/s}^2 \) Substituting these values into the equation: \[ N - 490 = 50 \times 0.49 \] Calculating the right-hand side: \[ 50 \times 0.49 = 24.5 \, \text{N} \] So the equation becomes: \[ N - 490 = 24.5 \] ### Step 5: Solve for the normal force \( N \) Now, we can solve for \( N \): \[ N = 490 + 24.5 = 514.5 \, \text{N} \] ### Conclusion The normal reaction exerted by the man on the floor of the elevator is \( 514.5 \, \text{N} \). ---

To solve the problem, we need to find the normal reaction exerted by the man on the floor of the elevator. Here’s the step-by-step solution: ### Step 1: Identify the forces acting on the man When the elevator is moving upwards with an acceleration, two main forces act on the man: 1. The weight of the man (downwards), which is given by \( W = mg \), where \( m \) is the mass of the man and \( g \) is the acceleration due to gravity. 2. The normal force (upwards), which we will denote as \( N \). ### Step 2: Write down the expressions for the forces ...
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A man of mass 50 kg is standing in an elevator. If elevator is moving up with an acceleration (g)/(3) then work done by normal reaction of elevator floor on man when elevator moves by a distance 12 m is (g=10 m//s^(2)) :-

Knowledge Check

  • A man of mass 90 kg is standing in an elevator whose cable broke suddenly. IF the elevator falls freely, the force exerted by the floor on the man is

    A
    90 N
    B
    90 g N
    C
    0 N
    D
    any negative value
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