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Assertion : 2,4-Dimethyl hex-2-ene has 4...

Assertion : 2,4-Dimethyl hex-2-ene has 4 stereoisomer
Reason : It show geometrical isomerism

A

If both assertion and reason are true and reason is the correct explanation of assertion.

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assertion is true but reason is false.

D

If both assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Compound**: - The compound in question is 2,4-Dimethylhex-2-ene. This indicates that we have a hexane chain (6 carbon atoms) with a double bond at the second carbon and two methyl groups at the second and fourth positions. 2. **Drawing the Structure**: - The structure of 2,4-Dimethylhex-2-ene can be drawn as follows: ``` CH3-CH=C(CH3)-CH2-CH(CH3)-CH3 ``` - This shows that at carbon 2, we have a double bond and a methyl group, and at carbon 4, we have another methyl group. 3. **Identifying Chiral Centers**: - A chiral carbon is defined as a carbon atom that is attached to four different groups. - In the structure, we need to check each carbon: - Carbon 2 (C=C) is not chiral because it has two identical methyl groups attached. - Carbon 4 is also not chiral because it has two identical groups (the two methyl groups). - The only potential chiral center is at carbon 3, which is attached to four different groups (CH3, CH2, H, and the rest of the carbon chain). - Therefore, there is **1 chiral center** in 2,4-Dimethylhex-2-ene. 4. **Calculating Stereoisomers**: - The formula for calculating the number of stereoisomers is \(2^n\), where \(n\) is the number of chiral centers. - Since we have 1 chiral center (\(n = 1\)), the number of stereoisomers is: \[ 2^1 = 2 \] - Thus, the assertion that 2,4-Dimethylhex-2-ene has 4 stereoisomers is **false**. 5. **Analyzing Geometrical Isomerism**: - Geometrical isomerism occurs in compounds with a double bond where there are different groups attached to the carbons of the double bond. - In this case, the double bond is between carbon 2 and carbon 3. However, both groups attached to carbon 2 are identical (two methyl groups). - Therefore, this compound does not exhibit geometrical isomerism, making the reason **false** as well. 6. **Conclusion**: - Both the assertion and the reason are false. Therefore, the correct answer is that both the assertion and reason are false. ### Final Answer: Both assertion and reason are false. ---
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