What is X in the following reaction
`KHSO_4+F_2rarrHF+X`

Options

A. a. `K_2SO_4`
B. b. `K_2S_2O_4`
C. c. `K_2S_2O_3`
D. d. `K_2S_2O_3`

Answer

To solve the reaction \( KHSO_4 + F_2 \rightarrow HF + X \), we need to identify what \( X \) is. Let's break it down step by step.

### Step 1: Analyze the Reactants
We have:
- \( KHSO_4 \) (Potassium hydrogen sulfate)
- \( F_2 \) (Fluorine gas)

### Step 2: Write the Products
We know one of the products is \( HF \) (Hydrofluoric acid). We need to determine what \( X \) is.

### Step 3: Balance the Reaction
1. **Count the Atoms:**
- From \( KHSO_4 \), we have:
- 1 Potassium (K)
- 1 Hydrogen (H)
- 1 Sulfur (S)
- 4 Oxygens (O)
- From \( F_2 \), we have:
- 2 Fluorines (F)

2. **Products:**
- We have \( HF \), which contributes:
- 1 Hydrogen (H)
- 1 Fluorine (F)

3. **Balancing Fluorine:**
- Since we have 2 Fluorines from \( F_2 \) and only 1 in \( HF \), we need another \( HF \) to balance:
\[ KHSO_4 + F_2 \rightarrow 2HF + X \]

### Step 4: Determine \( X \)
- Now, we have used:
- 2 Hydrogens (from 2 \( HF \))
- 2 Fluorines (from \( F_2 \))

- The remaining elements from \( KHSO_4 \) will form \( X \):
- We still have:
- 1 Potassium (K)
- 1 Sulfur (S)
- 4 Oxygens (O)

- The remaining compound formed will be \( K_2S_2O_8 \) (Dipotassium peroxodisulfate).

### Final Step: Write the Complete Reaction
\[ KHSO_4 + F_2 \rightarrow 2HF + K_2S_2O_8 \]

Thus, \( X \) is \( K_2S_2O_8 \).

### Conclusion
The final answer is:
\[ X = K_2S_2O_8 \]