Which one amongst of the following isomerism is shown by `[Pt(NH_3)_2Cl_(2)]?`

Options

A. a. Structrual
B. a. Geometrical
C. c. Optical
D. d. Conformational

Answer

To determine the type of isomerism exhibited by the complex `[Pt(NH₃)₂Cl₂]`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Coordination Number and Geometry**:
- The complex `[Pt(NH₃)₂Cl₂]` has a platinum (Pt) center with two ammonia (NH₃) ligands and two chloride (Cl) ligands.
- The coordination number of platinum in this complex is 4, which typically leads to a square planar geometry.

2. **Draw the Possible Structures**:
- In a square planar geometry, the ligands can be arranged in different ways. We can have:
- **Cis Isomer**: where the two identical ligands (NH₃) are adjacent to each other, and the two chloride ligands (Cl) are also adjacent.
- **Trans Isomer**: where the two identical ligands (NH₃) are opposite each other, and the two chloride ligands (Cl) are also opposite each other.

3. **Identify the Isomerism**:
- The two arrangements (cis and trans) represent geometric isomerism. In geometric isomerism, the same ligands are arranged differently in space, leading to different physical and chemical properties.

4. **Conclusion**:
- Since `[Pt(NH₃)₂Cl₂]` can exist in both cis and trans forms, it exhibits **geometric isomerism**.

### Final Answer:
The isomerism shown by `[Pt(NH₃)₂Cl₂]` is **geometric isomerism**.

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