Home
Class 12
PHYSICS
Two spherical numlei have mass numbers 2...

Two spherical numlei have mass numbers 216 and 64 with their radii `R_(1) and R_(2),` respectively. Then ratio, `(R_(1))/(R_(2))` is equal to

A

`3 : 2`

B

`1 : 3`

C

`1 : 2`

D

`2 : 3`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Two spherical nuclei have mass number 216 and 64 with their radii R_(1) and R_(2) respectively. The ratio, (R_(1))/(R_(2)) is equal to

If the radii of nuclei of ._(13)Al^(27) and ._(30)Zn^(64) are R_(1) and R_(2) respectively, then (R_(1))/(R_(2))=

Two soap bubbles A and B have radii r_(1) and r_(2) respectively. If r_(1) lt r_(2) than the excess pressure inside

Two spherical black bodies of radii R_(1) and R_(2) and with surface temperature T_(1) and T_(2) respectively radiate the same power. R_(1)//R_(2) must be equal to

Assertion : Two spherical shells have masses m_(1) and m_(2) . Their radii are r_(1) and r_(2) . Let r be the distance of a point from centre. Then gravitational field strength and gravitational potential both are equal to zero for O lt r lt r_(1) Reason : In the region r_(1) lt r lt r_(2) , gravitational field strength due to m_(2) is zero. But gravitational potential due to m_(2) is constant (but non-zero).

Two loops P and Q are made from a uniform wire. The radii of P and Q are R_(1) and R_(2) , respectively, and their moments of inertia about their axis of rotation are I_(1) and I_(2) , respectively. If (I_(1))/(I_(2))=4 , then (R_(2))/(R_(1)) is

Two concentric shells have masses M and m and their radii are R and r , respectively, where R gt r . What is the gravitational potential at their common centre?

A planet of mass M, has two natural satellites with masses m1 and m2. The radii of their circular orbits are R_(1) and R_(2) respectively. Ignore the gravitational force between the satellites. Define v_(1), L_(1), K_(1) and T_(1) to be, respectively, the orbital speed, angular momentum, kinetic energy and time period of revolution of satellite 1 , and v_(2), L_(2), K_(2) and T_(2) to be he corresponding quantities of satellite 2. Given m_(1)//m_(2) = 2 and R_(1)//R_(2) = 1//4 , match the ratios in List-I to the numbers in List-II.

Two reactions R_(2) and R_(2) have identical pre - exponential factors. Activations enery of R_(1) exceeds that of R_(2) by 10 kJ mol_(-1) . If k_(1) and k_(2) are rate constants for rate constants for reactions R_(1) and R_(2) respectively at 300k , then In (k_(2)/k_(1)) is equal to (R=8.314 J mol^(-1)K^(-1))

Two reactions R_(1) and R_(2) have identical pre - exponential factors. Activations enery of R_(1) exceeds that of R_(2) by 10 kJ mol_(-1) . If k_(1) and k_(2) are rate constants for rate constants for reactions R_(1) and R_(2) respectively at 300k , then In (k_(2)/k_(1)) is equal to (R=8.314 J mol^(-1)K^(-1))