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Assertion (A) If the frequency of the ap...

Assertion (A) If the frequency of the applied AC is doubled , then the power factor of a series R-L circuit decreases.
Reason (R ) Power factor of series R-L circuit is given by `costheta=(2R)/(sqrt(R^(2)+omega^(2)L^(2)))`

A

If both Assertion and Reason are true and Reason is correct explanation of Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

If Assertion is true but Reason is false.

D

If both Assertion and Reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the assertion and the reason given in the question regarding the power factor of a series R-L circuit when the frequency of the applied AC is doubled. ### Step-by-Step Solution: 1. **Understanding Power Factor**: The power factor (PF) of a circuit is defined as the cosine of the phase angle (φ) between the voltage and the current. For a series R-L circuit, the power factor can be expressed as: \[ \text{PF} = \cos(\phi) = \frac{R}{Z} \] where \( Z \) is the impedance of the circuit. 2. **Calculating Impedance**: The impedance \( Z \) of a series R-L circuit is given by: \[ Z = \sqrt{R^2 + (\omega L)^2} \] where \( \omega = 2\pi f \) is the angular frequency, and \( L \) is the inductance. 3. **Effect of Doubling Frequency**: If the frequency \( f \) is doubled, then the new frequency \( f' = 2f \) leads to a new angular frequency: \[ \omega' = 2\omega = 4\pi f \] The new impedance becomes: \[ Z' = \sqrt{R^2 + (4\pi f L)^2} \] 4. **New Power Factor**: The new power factor after doubling the frequency is: \[ \text{PF}' = \frac{R}{Z'} = \frac{R}{\sqrt{R^2 + (4\pi f L)^2}} \] 5. **Comparison of Power Factors**: To see if the power factor decreases, we compare \( Z \) and \( Z' \): - Initially, \( Z = \sqrt{R^2 + (2\pi f L)^2} \) - After doubling the frequency, \( Z' = \sqrt{R^2 + (4\pi f L)^2} \) Since \( (4\pi f L)^2 > (2\pi f L)^2 \), it follows that \( Z' > Z \). Therefore, the new power factor \( \text{PF}' \) will be less than the original power factor \( \text{PF} \). 6. **Conclusion**: The assertion that the power factor decreases when the frequency is doubled is true. The reason provided, which states the formula for power factor, is incorrect because it incorrectly includes a factor of 2. ### Final Answer: - Assertion (A) is **True**: If the frequency of the applied AC is doubled, then the power factor of a series R-L circuit decreases. - Reason (R) is **False**: The power factor formula provided is incorrect.
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