Home
Class 12
CHEMISTRY
CH(3)-CH(2)-CH=CH(2)+HBroverset("ROOR (p...

`CH_(3)-CH_(2)-CH=CH_(2)+HBroverset("ROOR (peroxide)")tounderset("Major")((X))+underset("Minor")((Y))XandY` respectively are

A

`BrCH_(2)-CH_(2)-CH=CH_(2)andC_(2)H_(5)-CHBr-CH_(3)`

B

`C_(2)H_(5)-CH_(2)-CH_(2)BrandBr-CH_(2)-CH_(2)-CH=CH_(2)`

C

`C_(2)H_(5)-CH_(2)-CH_(2)BrandC_(2)H_(5)-CHBr-CH_(3)`

D

`C_(2)H_(5)CHBr-CH_(3)andC_(2)H_(5)-CH_(2)-CH_(2)Br`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the reaction of 1-butene (CH₃-CH₂-CH=CH₂) with HBr in the presence of peroxide (ROOR). The presence of peroxide leads to the anti-Markovnikov addition of HBr to the alkene. ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactant is 1-butene (CH₃-CH₂-CH=CH₂) and HBr in the presence of peroxide. 2. **Understand the Peroxide Effect**: The peroxide effect causes the addition of HBr to follow the anti-Markovnikov rule. This means that the hydrogen (H) from HBr will add to the less substituted carbon atom of the double bond. 3. **Break the Double Bond**: The double bond between the two carbon atoms will break, leading to the formation of a carbocation. The two possible carbocations are: - If the H adds to the terminal carbon (C1), a secondary carbocation will form at C2. - If the H adds to C2, a primary carbocation will form at C1. 4. **Formation of Carbocations**: - **Carbocation 1**: H adds to C1 (less substituted), leading to a carbocation on C2: - CH₃-CH₂-CH⁺-CH₂ - **Carbocation 2**: H adds to C2 (more substituted), leading to a carbocation on C1: - CH₃-CH⁺-CH₂-CH₂ 5. **Nucleophilic Attack**: The bromide ion (Br⁻) will then attack the carbocation: - From Carbocation 1: Br⁻ will attack C2, leading to the major product (X): - **X (Major Product)**: CH₃-CH₂-CHBr-CH₃ (2-bromobutane) - From Carbocation 2: Br⁻ will attack C1, leading to the minor product (Y): - **Y (Minor Product)**: CH₃-CHBr-CH₂-CH₃ (1-bromobutane) 6. **Final Products**: - Major Product (X): 2-bromobutane (CH₃-CH₂-CHBr-CH₃) - Minor Product (Y): 1-bromobutane (CH₃-CHBr-CH₂-CH₃) ### Conclusion: The major product (X) is 2-bromobutane and the minor product (Y) is 1-bromobutane.
Promotional Banner

Similar Questions

Explore conceptually related problems

CH_(3)CH=CH_(2)+BrC Cl_(3)overset("Peroxide")to[A]

CH_(3)-CH=CH-CH_(2)-CH_(3) overset(HI)to underset("major")A Compound A is

In the following reaction H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH=CH_(2) overset(H_(2)O //H^(o+))(rarr) underset(("Major"),("product"))(A)underset(("Minor"),("product"))(B) The major product is

In the reaction X + Y underset(5^(@)C)overset(NaOH)(rarr) CH_(3)-overset(OH)overset(|)(CH)-underset(CH_(3))underset(|)(CH)-CHO (X) and (Y) Will respectively be :

CH_(3)-underset(CH_(3)) underset(|) (C)= CH_(2) underset("Peroxide") overset(HBr)to CH_(3)-underset(CH_(3)) underset(|) (CH)-CH_(2)Br reaction intermediate of this reaction is:

The order of reactivity of following alcohols with halogen acids is………. (A) CH_(3)CH_(2)-CH_(2)-OH (B) CH_(3CH_(2)-underset(CH_(3))underset(|)"CH"-OH (C ) CH_(3)CH_(2)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OH

Among these chain isomers are : (I) CH_(3)-CH_(3)-CH_(2)-CH_(2)-OH (II) CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3) (III) CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(3)

The type of isomerism shown by the following compounds is CH_(3)CH_(2)CH_(2)CH_(2)CH_(3),CH_(3)-overset(CH_(3))overset(|)(C)H-CH_(2)CH_(3),CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)

In following compound CH_(3)-CH_(2)-underset(CH_(3))overset(CH_(3))underset|overset(|)(C)-underset(CH_(3))underset(|)(CH)-overset(CH_(3))overset(|)(CH)-CH_(2)-CH_(3) The correct lowest set of locant is :

Write the name of the given compound CH_(3)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)underset(CH-CH_(3))underset(|)CH-CH_(2)-CH_(2)-overset(CH_(2))overset(|)CH-CH_(3)