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Three identical charges are placed at th...

Three identical charges are placed at the vertices of an equilateral triangle. The force experienced by each charge, (if `k = 1/4piepsi_(0)`) is

A

`2K(q^(2))/(r^(2))`

B

`(Kq^(2))/(2r^(2))`

C

`sqrt(3)K(q^(2))/(r^(2))`

D

`(Kq^(2))/(sqrt(2)r^(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the force experienced by each charge placed at the vertices of an equilateral triangle, we can follow these steps: ### Step 1: Understand the Configuration We have three identical charges, say \( Q \), placed at the vertices of an equilateral triangle. Let the distance between each pair of charges be \( R \). ### Step 2: Calculate the Force Between Two Charges Using Coulomb's Law, the force \( F \) between any two charges \( Q \) separated by a distance \( R \) is given by: \[ F = k \frac{Q^2}{R^2} \] where \( k = \frac{1}{4 \pi \epsilon_0} \). ### Step 3: Identify Forces Acting on One Charge Consider one charge (let's say charge at vertex A). It experiences forces due to the other two charges (at vertices B and C). Let the force exerted by charge B on charge A be \( F_1 \) and the force exerted by charge C on charge A be \( F_2 \). Since the charges are identical and symmetrically placed, we have: \[ F_1 = F_2 = F = k \frac{Q^2}{R^2} \] ### Step 4: Determine the Angle Between Forces The angle between the forces \( F_1 \) and \( F_2 \) is \( 60^\circ \) because the triangle is equilateral. ### Step 5: Calculate the Resultant Force To find the net force \( F \) acting on charge A due to charges B and C, we can use the law of cosines or the parallelogram law. The resultant force can be calculated as: \[ F = \sqrt{F_1^2 + F_2^2 + 2 F_1 F_2 \cos(60^\circ)} \] Substituting \( F_1 = F_2 = F \): \[ F = \sqrt{F^2 + F^2 + 2 F^2 \cdot \frac{1}{2}} = \sqrt{2F^2 + F^2} = \sqrt{3F^2} = \sqrt{3}F \] ### Step 6: Substitute for \( F \) Now substituting \( F = k \frac{Q^2}{R^2} \): \[ F = \sqrt{3} \cdot k \frac{Q^2}{R^2} \] ### Final Answer Thus, the force experienced by each charge is: \[ F = \sqrt{3} \cdot k \frac{Q^2}{R^2} \]
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