What is the potential energy of a 10 kg steel ball which has been raised vertically 9 m above the floor ?

Options

A. 441 joules
B. 98 joules
C. 90 joules
D. 882 joules

Explanation

To find the potential energy (PE) of a 10 kg steel ball raised vertically 9 m above the floor, we can use the formula for gravitational potential energy:

\[ PE = mgh \]

Where:
- \( PE \) is the potential energy,
- \( m \) is the mass of the object (in kg),
- \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)),
- \( h \) is the height above the reference point (in meters).

### Step-by-Step Solution:

1. **Identify the mass of the ball**:
- Given: \( m = 10 \, \text{kg} \)

2. **Identify the height above the floor**:
- Given: \( h = 9 \, \text{m} \)

3. **Use the standard value for acceleration due to gravity**:
- \( g \approx 9.8 \, \text{m/s}^2 \)

4. **Substitute the values into the potential energy formula**:
\[ PE = mgh = 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 9 \, \text{m} \]

5. **Calculate the potential energy**:
\[ PE = 10 \times 9.8 \times 9 = 882 \, \text{J} \]

6. **Final result**:
- The potential energy of the 10 kg steel ball raised 9 m above the floor is \( 882 \, \text{J} \).