What is the work done In joules if a 100-kg ball is raised to 3 m above the floor in 1 second ?

Options

A. 1960 joules
B. 980 joules
C. 2940 joules
D. 3240 joules

Explanation

To solve the problem of finding the work done when a 100-kg ball is raised to a height of 3 meters, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Mass of the ball (m) = 100 kg
- Height (h) = 3 m
- Acceleration due to gravity (g) = 9.8 m/s² (standard value)

2. **Understand the Formula for Work Done**:
- The work done (W) in raising an object against gravity is given by the formula:
\[ W = mgh \]
where:
- \( W \) = work done (in joules)
- \( m \) = mass of the object (in kg)
- \( g \) = acceleration due to gravity (in m/s²)
- \( h \) = height (in meters)

3. **Substitute the Values into the Formula**:
- Plugging in the values we have:
\[ W = (100 \, \text{kg}) \times (9.8 \, \text{m/s}^2) \times (3 \, \text{m}) \]

4. **Calculate the Work Done**:
- First, calculate \( mg \):
\[ mg = 100 \times 9.8 = 980 \, \text{N} \]
- Now, multiply by height (h):
\[ W = 980 \, \text{N} \times 3 \, \text{m} = 2940 \, \text{J} \]

5. **Final Answer**:
- The work done in raising the ball is:
\[ W = 2940 \, \text{J} \]

### Summary of the Solution:
The work done in raising a 100-kg ball to a height of 3 meters is **2940 joules**.