If a force of 30.6 kg acts on a 60 kg mass, calculate the resulting acceleration. (1 k.g of force = 9.8 newtons)

A. `5m//sec^2`
B. `2m//sec^2`
C. `0.5m//sec^2`
D. `9.8m//sec^2`

Options

A. `5m//sec^2`
B. `2m//sec^2`
C. `0.5m//sec^2`
D. `9.8m//sec^2`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Convert the force from kg to Newtons
Given that 1 kg of force is equal to 9.8 Newtons, we need to convert the force of 30.6 kg into Newtons.

\[ \text{Force (F)} = 30.6 \, \text{kg} \times 9.8 \, \text{N/kg} = 299.88 \, \text{N} \approx 300 \, \text{N} \]

### Step 2: Identify the mass
The mass (m) is given as 60 kg.

### Step 3: Apply Newton's second law of motion
According to Newton's second law of motion, the force acting on an object is equal to the mass of the object multiplied by its acceleration (a):

\[ F = m \cdot a \]

We can rearrange this equation to solve for acceleration:

\[ a = \frac{F}{m} \]

### Step 4: Substitute the values into the equation
Now we will substitute the values of force and mass into the equation we derived:

\[ a = \frac{300 \, \text{N}}{60 \, \text{kg}} \]

### Step 5: Calculate the acceleration
Now we perform the division:

\[ a = 5 \, \text{m/s}^2 \]

### Conclusion
The resulting acceleration is \(5 \, \text{m/s}^2\).

### Answer
The correct option is A. \(5 \, \text{m/s}^2\).

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