How far will a body free-fall in 1 second If released from rest ?

Options

A. 0.0 m
B. 4.9 m
C. 9.8 m
D. 19.6 m.

Explanation

To solve the problem of how far a body will free-fall in 1 second when released from rest, we can use the second equation of motion. Here are the steps:

### Step-by-Step Solution:

1. **Identify the Variables**:
- Initial velocity (u) = 0 m/s (since the body is released from rest)
- Time (t) = 1 second
- Acceleration (a) = g = 9.8 m/s² (acceleration due to gravity)

2. **Use the Second Equation of Motion**:
The second equation of motion states:
\[ s = ut + \frac{1}{2} a t^2 \]
where:
- \( s \) = displacement
- \( u \) = initial velocity
- \( a \) = acceleration
- \( t \) = time

3. **Substitute the Known Values**:
Since the initial velocity \( u = 0 \):
\[ s = 0 \cdot t + \frac{1}{2} g t^2 \]
Now substitute \( g = 9.8 \, \text{m/s}^2 \) and \( t = 1 \, \text{s} \):
\[ s = \frac{1}{2} \cdot 9.8 \cdot (1)^2 \]

4. **Calculate the Displacement**:
\[ s = \frac{1}{2} \cdot 9.8 \cdot 1 = \frac{9.8}{2} = 4.9 \, \text{meters} \]

5. **Conclusion**:
The body will fall a distance of 4.9 meters in 1 second.

### Final Answer:
The body will free-fall **4.9 meters** in 1 second.

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