If the piece of glass 10kg were suspended in air, It would weight (the buoyancy of air is neglected)

Options

A. 100 Newtons
B. 50 Newtons
C. 10 Newtons
D. 600 Newtons

Explanation

To solve the problem, we need to calculate the weight of a 10 kg piece of glass suspended in air, neglecting the buoyancy of air. The weight of an object can be calculated using the formula:

\[ \text{Weight} (W) = \text{mass} (m) \times \text{acceleration due to gravity} (g) \]

### Step-by-Step Solution:

1. **Identify the mass of the glass**:
The mass of the glass is given as \( m = 10 \, \text{kg} \).

2. **Identify the acceleration due to gravity**:
The standard value for the acceleration due to gravity is \( g = 10 \, \text{m/s}^2 \).

3. **Use the weight formula**:
Substitute the values of mass and gravity into the weight formula:
\[ W = m \times g \]

4. **Calculate the weight**:
\[ W = 10 \, \text{kg} \times 10 \, \text{m/s}^2 = 100 \, \text{N} \]

5. **Conclusion**:
Therefore, the weight of the 10 kg piece of glass suspended in air is \( 100 \, \text{N} \).

### Final Answer:
The weight of the piece of glass is \( 100 \, \text{N} \).

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