A Grignard reagent , such as `(CH_3MgBr)` will react with `C_2H_5OH` and then with acidified water to produce

Options

A. a secondary or tertiary alcohol
B. an aldehyde
C. a ketone
D. none of the above

Explanation

To solve the question regarding the reaction of the Grignard reagent `(CH₃MgBr)` with `C₂H₅OH` followed by acidified water, we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**: The Grignard reagent is `(CH₃MgBr)` and the alcohol is `C₂H₅OH`.

2. **Understand the Nature of Grignard Reagents**: Grignard reagents are strong nucleophiles and bases. They can react with electrophiles or abstract protons from acidic compounds.

3. **Reaction with Ethanol (C₂H₅OH)**:
- When `(CH₃MgBr)` reacts with `C₂H₅OH`, it primarily acts as a base rather than a nucleophile because the product formed by nucleophilic attack would be unstable.
- The Grignard reagent abstracts the acidic hydrogen from the hydroxyl group of ethanol.

\[ \text{C₂H₅OH} + \text{CH₃MgBr} \rightarrow \text{C₂H₅O}^- + \text{CH₄} + \text{MgBr}^+ \]

Here, methane `(CH₄)` is formed as a byproduct.

4. **Reaction with Acidified Water**:
- The alkoxide ion `(C₂H₅O^-)` formed in the previous step will then react with acidified water (H⁺ from the acid).
- This reaction will regenerate the alcohol:

\[ \text{C₂H₅O}^- + \text{H}_2\text{O} \rightarrow \text{C₂H₅OH} + \text{OH}^- \]

5. **Final Products**:
- The final products of the entire reaction sequence are methane `(CH₄)` and ethanol `(C₂H₅OH)`. However, since the question asks for the product after both reactions, we focus on the alkane produced.

6. **Conclusion**: The primary product of the reaction is methane `(CH₄)`, and since the question asks what is produced after both reactions, the answer is **none of the above** if the options provided do not include methane.

### Final Answer:
The reaction produces **methane (CH₄)** and the answer to the question is **none of the above**.