Assertion: Amongest the halogens, fluorine can oxidise the
elements to the highest oxidation- state.
Reason: Due to small size of fluoride ion, it is difficult to
oxidise fluoride ion to fluorine. Hence reverse reaction takes place
more easily.
Assertion: Amongest the halogens, fluorine can oxidise the
elements to the highest oxidation- state.
Reason: Due to small size of fluoride ion, it is difficult to
oxidise fluoride ion to fluorine. Hence reverse reaction takes place
more easily.
elements to the highest oxidation- state.
Reason: Due to small size of fluoride ion, it is difficult to
oxidise fluoride ion to fluorine. Hence reverse reaction takes place
more easily.
A
Assertion is true but the Reason is false
B
Assertion is false, Reason is true
C
Both Assertion and Reason are true and the Reason is a correct explanation of the Reason.
D
Both Assertion and Reason are true but Reason is not a correct explanation of the assertion.
Text Solution
AI Generated Solution
The correct Answer is:
To solve the given question, we need to analyze both the assertion and the reason provided.
**Step 1: Analyze the Assertion**
The assertion states that "Amongst the halogens, fluorine can oxidize the elements to the highest oxidation state."
- Fluorine (F2) is indeed the strongest oxidizing agent among the halogens. This is due to its high electronegativity and small atomic size, which allow it to attract electrons very effectively. Therefore, the assertion is **true**.
**Step 2: Analyze the Reason**
The reason states that "Due to the small size of the fluoride ion, it is difficult to oxidize the fluoride ion to fluorine. Hence, the reverse reaction takes place more easily."
- The fluoride ion (F-) is indeed small and has a high electron density, making it a weak reducing agent. The conversion of fluoride ion (F-) to fluorine (F2) is not favored because F- is a strong base and does not easily lose electrons. Therefore, this statement is also **true**.
**Step 3: Determine the Relationship Between Assertion and Reason**
While both statements are true, we need to determine if the reason correctly explains the assertion. The assertion is about fluorine's ability to oxidize other elements, while the reason discusses the difficulty of oxidizing fluoride ions back to fluorine. The two statements are related to different aspects of fluorine's chemistry. Therefore, the reason does not provide a correct explanation for the assertion.
**Conclusion**
Both the assertion and reason are true, but the reason is not the correct explanation of the assertion.
**Final Answer:**
Both assertion and reason are true, but the reason is not the correct explanation of the assertion.
---
To solve the given question, we need to analyze both the assertion and the reason provided.
**Step 1: Analyze the Assertion**
The assertion states that "Amongst the halogens, fluorine can oxidize the elements to the highest oxidation state."
- Fluorine (F2) is indeed the strongest oxidizing agent among the halogens. This is due to its high electronegativity and small atomic size, which allow it to attract electrons very effectively. Therefore, the assertion is **true**.
**Step 2: Analyze the Reason**
The reason states that "Due to the small size of the fluoride ion, it is difficult to oxidize the fluoride ion to fluorine. Hence, the reverse reaction takes place more easily."
...
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Assertion : Decomposition of hydrogen peroxide is an example of disproportionation reaction. Reason : In a disproportionation reaction, an element in one oxidation state is simultaneously oxidised and reduced .
Assertion: The carbonate of lithium decomposes easily on heating. Reason: Lithium being very small in size polarises large carbonate ion leading to the formation of more stable Li_(2)O and CO_(2) .
The IUPAC definition of a transition element is that it is an element that has an incomplete d-subshell in either the neutral atom or its ion. Thus the group 12 elements are member of the d-block but are not transition elements. Chemically solft members of the d-block occurs as sulphide minerals and are partially oxidised to obtain the metal, the more electropositive 'hard' metals occurs as oxides and are extracted by reduction. Opposite to p-block elements, the higher oxidation states are favoured by the heavier elements of d-block Metals on the right of the d-block tend to exist in low oxidation states and form complexes with the ligands. Square-planar complexes are common for the platinum metals and gold in oxidation states that yield d^8 electronic configuration, which include RH(I),Ir(I),Pd(II),Pt(II) and Au(III). The most distinctive features/properties of transition metal complex is their wide range of colours.The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron.It is important to note that (a) in absence of ligand, crystal field spilling does not occur and hence the substances is colourless, (b) the type of ligand also influences the colour of the complexes. Which of the following has dsp^2 hybridisation and is diamagnetic in nature ? (i) Na_4[Cr(CO)_4] , (ii) [Ni(DMGH)_2] , (iii) [PtHBr(PEt_3)_2] (iv) [As(SCN)_4]^(3-) , (v) [AuBr_4]^(-)
If an element can exist in several oxidation states, it is convernient to display the reduction potentials correspondingg to the various half reactions in diagrammatic form, know as latimer diagram the latimer diagram for chlorine in acid solutio is CIO_(4)^(-)overset(+1.20V)toCiO_(3)^(-)overset(+1.18V)toHClO_(2)overset(+1.60V)toHClOoverset(1.67V)toCl_(2)overset(1.36V)toCl^(-) in basic solution. ClO_(4)^(-)overset(0.37V)toClO_(3)^(-)overset(0.30V)toClO_(2)^(-)overset(0.68V)toClO^(-)overset(0.42V)toCl_(2)overset(1.36V)toCl^(-) The standard potentials for two nonadjacent species can also be calculateed by using the concept that triangleG^(@) as an additive property but potential is not an additive property and triangleG^(@)=-nFx^(0) . if a given oxidation stateis a stronger oxidising agent than the next higher oxidation state, disproportionation can occur. The reverse of disproportionation is called comproportionation. The relative stabilities of the oxidation state can also be understood by drawing a graph of triangleG^(@)//F against oxidation state, known as frost diagram, choosing the stability of zero oxidation state arbitrarily as zero. The most stable oxidation state of a species lies lowest in the diagram, disproportionation is spontaneous if the species lies above a straight line joining its two product species. Q. For a hypothetical element, the frost diagram is shown in figure.? which of the following oxidation state is least stable?
If an element can exist in several oxidation states, it is convernient to display the reduction potentials correspondingg to the various half reactions in diagrammatic form, know as latimer diagram the latimer diagram for chlorine in acid solutio is CIO_(4)^(-)overset(+1.20V)toCiO_(3)^(-)overset(+1.18V)toHClO_(2)overset(+1.60V)toHClOoverset(1.67V)toCl_(2)overset(1.36V)toCl^(-) in basic solution. ClO_(4)^(-)overset(0.37V)toClO_(3)^(-)overset(0.30V)toClO_(2)^(-)overset(0.68V)toClO^(-)overset(0.42V)toCl_(2)overset(1.36V)toCl^(-) The standard potentials for two nonadjacent species can also be calculateed by using the concept that triangleG^(@) as an additive property but potential is not an additive property and triangleG^(@)=-nFx^(0) . if a given oxidation stateis a stronger oxidising agent than the next higher oxidation state, disproportionation can occur. The reverse of disproportionation is called comproportionation. The relative stabilities of the oxidation state can also be understood by drawing a graph of triangleG^(@)//F against oxidation state, known as frost diagram, choosing the stability of zero oxidation state arbitrarily as zero. The most stable oxidation state of a species lies lowest in the diagram, disproportionation is spontaneous if the species lies above a straight line joining its two product species. Q. What is the potential couple (ClO^(-))/(Cl^(-)) at pH=14 ?
If an element can exist in several oxidation states, it is convernient to display the reduction potentials correspondingg to the various half reactions in diagrammatic form, know as latimer diagram the latimer diagram for chlorine in acid solutio is CIO_(4)^(-)overset(+1.20V)toCiO_(3)^(-)overset(+1.18V)toHClO_(2)overset(+1.60V)toHClOoverset(1.67V)toCl_(2)overset(1.36V)toCl^(-) in basic solution. ClO_(4)^(-)overset(0.37V)toClO_(3)^(-)overset(0.30V)toClO_(2)^(-)overset(0.68V)toClO^(-)overset(0.42V)toCl_(2)overset(1.36V)toCl^(-) The standard potentials for two nonadjacent species can also be calculateed by using the concept that triangleG^(@) as an additive property but potential is not an additive property and triangleG^(@)=-nFx^(0) . if a given oxidation stateis a stronger oxidising agent than the next higher oxidation state, disproportionation can occur. The reverse of disproportionation is called comproportionation. The relative stabilities of the oxidation state can also be understood by drawing a graph of triangleG^(@)//F against oxidation state, known as frost diagram, choosing the stability of zero oxidation state arbitrarily as zero. The most stable oxidation state of a species lies lowest in the diagram, disproportionation is spontaneous if the species lies above a straight line joining its two product species. Q. Which of the following statement is correct?
Assertion (A) The carbonate of lithium decomposes easily on heating to form lithium oxide and CO_(2) . Reason (R) Lithium being very small in size polarises large carbonate ion leading to the formation of more stable Li_(2)O and CO_(2) .
All the noble gases are colourless and tasteless monoatomic gases. In general, noble gases are least reactive and their inertness to chemical reactivity is attributed to the following reasons. Reactive and their inertness to chemical reactivity is attributed to the following reasons. (i)Except helium, all have completely filled ns^(2)np^(6) electronic configuration in their valence shells. (ii)All have high ionisation enthalpy and more positive electron gain enthalpy. However, a number of xenon compounds mainly with most electronegative elements like fluorine and oxygen have been synthesized under different conditions and fluorides of xenon have been used as an oxidising agent and a fluorinating agent in many of the chemical reactions Select the correct statement.
All the noble gases are colourless and tasteless monoatomic gases. In general, noble gases are least reactive and their inertness to chemical reactivity is attributed to the following reasons. Reactive and their inertness to chemical reactivity is attributed to the following reasons. (i)Except helium, all have completely filled ns^(2)np^(6) electronic configuration in their valence shells. (ii)All have high ionisation enthalpy and more positive electron gain enthalpy. However, a number of xenon compounds mainly with most electronegative elements like fluorine and oxygen have been synthesized under different conditions and fluorides of xenon have been used as an oxidising agent and a fluorinating agent in many of the chemical reactions The correct order of the abundance of various noble gases in air is :
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