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The radius of a circular loop is r and a...

The radius of a circular loop is r and a current i is flowing in it. The equivalent magnetic moment will be

A

`pir^2i`

B

`ir `

C

`2piir`

D

`i/(r2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Here, r is radius of loop
So, area of loop = `pir^2`
Therefore , its magnetic moment will be `pir^2xxi`
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