Which of the following relations between weber, second, ampere and volt be correct ?

Options

A. weber/second =volt
B. weber x second = volt
C. weber/second = ampere
D. weber x second = ampere

Explanation

To solve the question regarding the correct relation between Weber, second, ampere, and volt, we need to analyze the definitions and relationships between these units.

### Step-by-Step Solution:

1. **Understanding the Units**:
- **Weber (Wb)**: The unit of magnetic flux.
- **Second (s)**: The unit of time.
- **Ampere (A)**: The unit of electric current.
- **Volt (V)**: The unit of electric potential (or electromotive force).

2. **Using Faraday's Law of Electromagnetic Induction**:
- Faraday's law states that the induced electromotive force (emf, denoted as \( e \)) in a closed loop is equal to the rate of change of magnetic flux through the loop.
- Mathematically, this is expressed as:
\[ e = -\frac{d\Phi}{dt} \]
where \( \Phi \) is the magnetic flux.

3. **Substituting Units**:
- The unit of magnetic flux \( \Phi \) is Weber (Wb).
- The unit of time \( t \) is second (s).
- The induced emf \( e \) is measured in volts (V).
- Therefore, we can rewrite the equation in terms of units:
\[ \text{Volt} = \frac{\text{Weber}}{\text{Second}} \]
This implies:
\[ \text{Weber per second} = \text{Volt} \]

4. **Analyzing the Options**:
- From our derivation, we see that the relation \( \text{Weber per second} = \text{Volt} \) is valid.
- Now, looking at the options provided:
- Option A: Weber per second = Volt (Correct)
- Option B: Weber × second = Volt (Incorrect)
- Option C: Weber per second = Amperes (Incorrect)
- Option D: Weber × second = Amperes (Incorrect)

5. **Conclusion**:
- The correct relation among the given options is:
\[ \text{Weber per second} = \text{Volt} \]
Therefore, the answer is **Option A**.