The` [OH^-] `in a solution is `1xx10^(-8)` . The pH of the solution is

Options

A. `10.0`
B. `8.0`
C. `6.0`
D. `4.0`

Explanation

To find the pH of a solution given the hydroxide ion concentration \([OH^-]\), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given information**:
We have the hydroxide ion concentration \([OH^-] = 1 \times 10^{-8} \, \text{M}\).

2. **Calculate the pOH**:
The pOH can be calculated using the formula:
\[ pOH = -\log[OH^-] \]
Substituting the given concentration:
\[ pOH = -\log(1 \times 10^{-8}) \]
This simplifies to:
\[ pOH = -(-8) = 8 \]

3. **Use the relationship between pH and pOH**:
We know that:
\[ pH + pOH = 14 \]
Now, substituting the value of pOH we just calculated:
\[ pH + 8 = 14 \]

4. **Solve for pH**:
Rearranging the equation gives:
\[ pH = 14 - 8 = 6 \]

5. **Final answer**:
Therefore, the pH of the solution is:
\[ pH = 6.0 \]