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A force acts on a 30 g particle in such ...

A force acts on a 30 g particle in such a way that the position of the particle as a function of time is given by `x = 3t - 4t^2 + t^3` where x is in meters and t is in seconds. The work done during the first 4 second is

A

530 mJ

B

490 mJ

C

450 mJ

D

2.28J

Text Solution

Verified by Experts

The correct Answer is:
D
`W=(1)/(2)m(v_(4)^(2)-v_(0)^(2))`
`v=(dx)/(dt)=3-8t+3t^(2)`
`:. V_(0)=3 m//s and v_(4)=19 m//s `
`:. W=(1)/(2) xx 0.03xx(19^(2)-3^(2))=5.28J`
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