26 ml of ` CO_(2)` are passed over hot coke . The maximum volume of CO formed is :

Options

A. 32 ml
B. 52 ml
C. 15 ml
D. 10 ml

Explanation

To solve the problem of determining the maximum volume of CO formed when 26 ml of CO₂ is passed over hot coke, we can follow these steps:

### Step-by-Step Solution:

1. **Write the Balanced Chemical Equation**:
The reaction between carbon dioxide (CO₂) and carbon (from coke) can be represented as:
\[ \text{CO}_2(g) + \text{C}(s) \rightarrow 2 \text{CO}(g) \]
This equation indicates that one mole of CO₂ reacts with one mole of carbon to produce two moles of carbon monoxide (CO).

2. **Determine the Stoichiometric Ratios**:
From the balanced equation, we see that:
- 1 mole of CO₂ produces 2 moles of CO.
This means that for every volume of CO₂, we will get double that volume of CO.

3. **Calculate the Volume of CO Produced**:
Given that we have 26 ml of CO₂, we can calculate the volume of CO produced using the stoichiometric ratio:
\[ \text{Volume of CO} = 2 \times \text{Volume of CO}_2 \]
Substituting the given volume:
\[ \text{Volume of CO} = 2 \times 26 \text{ ml} = 52 \text{ ml} \]

4. **Conclusion**:
The maximum volume of CO formed from 26 ml of CO₂ is 52 ml.

### Final Answer:
The maximum volume of CO formed is **52 ml**.