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The volume of .10 voľ H2O, required to l...

The volume of .10 voľ `H_2O,` required to liberate 500 ml of `O_2` at NTP is:

A

125 ml

B

100 ml

C

25 ml

D

50 ml

Text Solution

Verified by Experts

The correct Answer is:
D

10 vol. ` H_(2)O_(2)` means that 1 ml `H_(2)O_(2)` gives 10 ml ` O_(2)` , Thus 50 ml `H_(2)O_(2)` will give 500 ml ` O_(2)` .
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