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CH-=CH overset(O(3)//NaOH)to X overset(Z...

`CH-=CH overset(O_(3)//NaOH)to X overset(Zn//CH_(3)COOH)to Y` . Y is

A

`CH_(3)OH `

B

`CH_(3)COOH`

C

`CH_(3)CH_(2)OH`

D

`CHO-CHO

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To solve the problem step by step, we will analyze the reactions taking place. ### Step 1: Identify the starting material The starting material is acetylene, which has the formula \( CH \equiv CH \). ### Step 2: Ozonolysis of acetylene When acetylene is treated with ozone (\( O_3 \)) in the presence of sodium hydroxide (\( NaOH \)), it undergoes ozonolysis. This reaction leads to the formation of an ozonide. The ozonide formed from acetylene can be represented as: \[ \text{Ozonide: } \text{(CHO)}_2 \] ### Step 3: Reduction of ozonide The ozonide is then treated with zinc (\( Zn \)) and acetic acid (\( CH_3COOH \)). This step is a reduction process. The ozonide breaks down into smaller carbonyl compounds. ### Step 4: Identify the product Y The product formed after the reduction of the ozonide with zinc and acetic acid is glyoxal, which has the structure: \[ \text{Glyoxal: } CHO-CHO \] Thus, the final product \( Y \) is glyoxal, represented as \( C_2H_2O_2 \) or \( CHO-CHO \). ### Final Answer Y is glyoxal (CHO-CHO). ---
To solve the problem step by step, we will analyze the reactions taking place. ### Step 1: Identify the starting material The starting material is acetylene, which has the formula \( CH \equiv CH \). ### Step 2: Ozonolysis of acetylene When acetylene is treated with ozone (\( O_3 \)) in the presence of sodium hydroxide (\( NaOH \)), it undergoes ozonolysis. This reaction leads to the formation of an ozonide. The ozonide formed from acetylene can be represented as: ...
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