Home
Class 12
PHYSICS
Draw the direction of frictionn force in...

Draw the direction of frictionn force in the followign cases. If rolling object is

A

`(5sqrt(2))/(3)N`

B

`(5)/(3sqrt(2))N`

C

`(5)/(sqrt(2))N`

D

`(5)/(2sqrt(3))N`

Text Solution

Verified by Experts

The correct Answer is:
B

`Mgsintheta-f=ma_(cm)` . . . (i)
`f_(R)=(MR^(2))/(2)((a_(mc))/(R))`
`f=(Ma_(cm))/(2)`
or `a_(cm)=(2f)/(M)`
so `mgsintheta-f=M((2f)/(M))`
`f=(mgsintheta)/(3)`
`f=(1)/(2)xx(10)/(3)xx(1)/(sqrt(2))=(5)/(3sqrt(2))` newton
Promotional Banner

Similar Questions

Explore conceptually related problems

In the above problem, direction of friction force is

Figure (a) and (b) shows two different arrangements of a spool being pulled with a constant force F in each case. Identify the direction of motion of the centre of mass, and the direction of friction force in each case. a. The CM moves along………………. x -axis . b. The friction force acts along…………………. x -axis. c. The CM moves along ..... x -axis. d. The friction force acts along…………….. x -axis.

(i) Explain why friction is necessary to make the disc to roll in the direction indicated. (ii) Give the direction of frictional force at B , and the sense of frictional torque, before perfect rolling begins. (iii) What is the force of friction after perfect rolling begins?

A spool is pulled by a force in vertical direction as shown in figure . What is the direction of friction in this case? The spool does not loose contact with the ground.

Find instantaneous direction of force in following cases (magnetic field and velocity are indicated )

In which of the following cases the net force is not zero ?

Find the instantaneous direction of force in following case (magnetic field and velocity are indicated)

Work done by friction in case of pure rolling

A force of 7N acts on an object. The displacement is, say 8m, in the direction of the force, Let us take it that the force acts on the object throughout the displacement. What is the work done in this case ?

A force of 5 N is acting on an object. The object is displaced through 2 m in the direction of the force (Fig. 11.2). If the force acts on the object all through the displacement, then work done is 5 N xx 2 m =10 N m or 10 J .