When Ag+ reacts with excess of sodium-thio sulphate then the obtained species having charges & geometry respectively:

Options

A. `-3`:Linear
B. `-2`,tetrahedral
C. `-1`,square planer
D. `-3`,square planar

Explanation

To solve the problem, we need to analyze the reaction between Ag⁺ and sodium thiosulfate (Na₂S₂O₃) and determine the charge and geometry of the resulting complex.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have silver ion (Ag⁺) and sodium thiosulfate (Na₂S₂O₃) as reactants.

2. **Understand the Reaction**:
- When Ag⁺ reacts with excess sodium thiosulfate, it forms a complex ion. The thiosulfate ion (S₂O₃²⁻) acts as a ligand and coordinates with the Ag⁺ ion.

3. **Formation of the Complex**:
- The reaction can be represented as:
\[ \text{Ag}^+ + 2 \text{Na}_2\text{S}_2\text{O}_3 \rightarrow \text{Na}_3[\text{Ag}(\text{S}_2\text{O}_3)_2] + \text{NaBr} \]
- The complex formed is \([\text{Ag}(\text{S}_2\text{O}_3)_2]^{3-}\).

4. **Determine the Charge of the Complex**:
- The charge of the complex ion is calculated as follows:
- Ag⁺ contributes +1 charge.
- Each thiosulfate ion (S₂O₃²⁻) contributes -2 charge. Since there are two thiosulfate ions, the total contribution from thiosulfate is -4.
- Therefore, the overall charge of the complex is:
\[ +1 + (-4) = -3 \]

5. **Determine the Geometry of the Complex**:
- The coordination number of Ag⁺ in this complex is 2, as it is bonded to two thiosulfate ligands.
- For a coordination number of 2, the hybridization is sp, which corresponds to a linear geometry.

6. **Final Answer**:
- The charge of the complex is -3 and the geometry is linear.

### Summary:
- The obtained species has a charge of -3 and a geometry that is linear.