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If maximum energy is stored in capacitor...

If maximum energy is stored in capacitor at t = 0 then find the time after which current in the circuit will be maximum.

A

a. `(pi)/(2)ms`

B

b. `(pi)/(4)ms`

C

c. `pi ms`

D

d. `2ms`

Text Solution

Verified by Experts

The correct Answer is:
B
In L-C oscillation total time in one complete cycle.
`T=2pisqrt(LC)`
`T=2pisqrt(25xx10^(-3)xx10xx10^(-6))` ltbr `T=2pisqrt(25xx10^(-8))`
`T=2pixx5xx10^(-4)`
`T=pixx10^(-3)sec`
after time `(T)/(4)` capacitor is fully closed
then `(T)/(4)=(pixx10^(-3))/(4)=(pi)/(4)ms`
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