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A transformer consists of 500 turn in p...

A transformer consists of 500 turn in primary coil and 10 turns in secondary coilk with the load of `10 Omega ` Find out current in the primary coil when the voltage across secondary coil 50V.

A

5A

B

.1A

C

10A

D

2A

Text Solution

Verified by Experts

The correct Answer is:
B
`(V_(P))/(V_(s))=(N_(P))/(N_(S))`
`(V_(P))/(V_(S))=(500)/(10)`
`V_(P)=2500`
`i_(s)=(V_(S))/(R)=(50)/(10)=5A`
`i_(s)=(V_(S))/(R)=(50)/(10)=5A`
`(i_(p))/(i_(s))=(v_(S))/(v_(P))`
`(i_(p))/(5)=(500)/(2500)`
`i_(p)=(1)/(5)xx5=1A`
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