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C(7)H(10)O reacts with CH(3)MgBr r to gi...

`C_(7)H_(10)O` reacts with `CH_(3)MgBr` r to give a compound `C_(8)H_(10)O` which gives the test with iodoform, than fine out structure of A

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Text Solution

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The correct Answer is:
To solve the problem, we need to identify the structure of compound A (C7H10O) that reacts with CH3MgBr to yield a compound C8H10O, which gives a positive iodoform test. ### Step-by-step Solution: 1. **Identify the Reactants and Products:** - The starting compound has the formula C7H10O. - It reacts with CH3MgBr (methyl magnesium bromide), which is a Grignard reagent. - The product has the formula C8H10O and gives a positive iodoform test. 2. **Understanding the Iodoform Test:** - The iodoform test is positive for compounds that have a methyl ketone (RCOCH3) or a secondary alcohol that can be oxidized to a methyl ketone. - Therefore, the product C8H10O must contain a structure that can yield a methyl ketone. 3. **Reaction with Grignard Reagent:** - Grignard reagents react with carbonyl compounds (like aldehydes and ketones) to form alcohols. - The reaction can be represented as: \[ \text{C7H10O} + \text{CH3MgBr} \rightarrow \text{C8H10O (after hydrolysis)} \] - The product will have an additional carbon from the Grignard reagent. 4. **Possible Structures for C7H10O:** - We need to consider possible structures for C7H10O that can lead to a product with a methyl ketone after the reaction. - A likely candidate for C7H10O is an unsaturated aldehyde or ketone. 5. **Testing the Structure:** - Let's assume C7H10O is 3-hexanone (an example structure). - The reaction with CH3MgBr would yield: \[ \text{3-hexanone} + \text{CH3MgBr} \rightarrow \text{4-heptanol (after hydrolysis)} \] - The resulting compound (4-heptanol) can be oxidized to 3-heptanone, which is a methyl ketone and will give a positive iodoform test. 6. **Conclusion:** - After analyzing the structures and reactions, we conclude that the structure of compound A (C7H10O) is likely to be 3-hexanone, which upon reaction with CH3MgBr gives a product that can yield a methyl ketone, thus passing the iodoform test. ### Final Answer: The structure of compound A (C7H10O) is 3-hexanone.
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