Home
Class 12
PHYSICS
A coil is placed in y-z plane making an ...

A coil is placed in y-z plane making an angle of `30^(@)` with x-axis . The current through coil is I, and number of turns are N. If a magnetic field of strength 'B' is applied in positive x-direction, then find the torque experienced by coil: (Radius of coil is R)
`(N = 100, I = 1A, r = 2m , B = 1/pi T)`

A

`100 N-m`

B

`50 N-m`

C

`200 N-m`

D

`150 N-m`

Text Solution

AI Generated Solution

The correct Answer is:
To find the torque experienced by the coil, we can follow these steps: ### Step 1: Understand the Torque Formula The torque (\(\tau\)) experienced by a coil in a magnetic field is given by the formula: \[ \tau = \mathbf{M} \times \mathbf{B} \] where \(\mathbf{M}\) is the magnetic moment vector and \(\mathbf{B}\) is the magnetic field vector. ### Step 2: Calculate the Magnetic Moment The magnetic moment (\(\mathbf{M}\)) of the coil can be calculated using the formula: \[ \mathbf{M} = N \cdot I \cdot A \] where: - \(N\) = number of turns of the coil - \(I\) = current through the coil - \(A\) = area of the coil ### Step 3: Calculate the Area of the Coil The area \(A\) of a circular coil is given by: \[ A = \pi R^2 \] Given that the radius \(R = 2 \, \text{m}\), we can calculate: \[ A = \pi (2^2) = 4\pi \, \text{m}^2 \] ### Step 4: Substitute Values into the Magnetic Moment Formula Now substituting the values into the magnetic moment formula: - \(N = 100\) - \(I = 1 \, \text{A}\) - \(A = 4\pi \, \text{m}^2\) Thus, \[ \mathbf{M} = 100 \cdot 1 \cdot 4\pi = 400\pi \, \text{A m}^2 \] ### Step 5: Calculate the Torque The torque can also be expressed as: \[ \tau = M \cdot B \cdot \sin(\theta) \] where \(\theta\) is the angle between the magnetic moment and the magnetic field. Here, \(\theta = 30^\circ\) and \(\sin(30^\circ) = \frac{1}{2}\). Given \(B = \frac{1}{\pi} \, \text{T}\), we can substitute the values into the torque formula: \[ \tau = (400\pi) \cdot \left(\frac{1}{\pi}\right) \cdot \frac{1}{2} \] ### Step 6: Simplify the Expression Now simplifying the expression: \[ \tau = 400 \cdot \frac{1}{2} = 200 \, \text{N m} \] ### Final Answer The torque experienced by the coil is: \[ \tau = 200 \, \text{N m} \] ---

To find the torque experienced by the coil, we can follow these steps: ### Step 1: Understand the Torque Formula The torque (\(\tau\)) experienced by a coil in a magnetic field is given by the formula: \[ \tau = \mathbf{M} \times \mathbf{B} \] where \(\mathbf{M}\) is the magnetic moment vector and \(\mathbf{B}\) is the magnetic field vector. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The magnetic moment of a current I carrying circular coil of radius r and number of turns N varies as

The magnetic moment of a current (i) carrying circular coil of radius (r) and number of turns (n) varies as

A circular coil of n turns and radius r carries a current I. The magnetic field at the centre is

If the current (I) flowing through a circular coil, its radius (R ) and number of turns (N) in it are each doubled, magnetic flux density at its centre becomes:

A circular coil of 25 turns and radius of 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of coil. If the current in the coil is 5 A, then total torque experienced by the coil is

A circular coil carrying a current I has radius R and number of turns N. If all the three, i.e., the current I, radius R and number of turns N are doubled, then, magnetic, field at its centre becomes:

A current I flows in a circular coil of radius r. If the coil is placed in a uniform magnetic field B with its plane parallel to the field, magnitude of the torque that acts on the coil is

A circular coil of radius 2R is carrying current 'i' . The ratio of magnetic fields at the centre of the coil and at a point at a distance 6R from the centre of the coil on the axis of the coil is

Two coils are having magnetic field B and 2B at their centres and current i and 2i then the ratio of their radius is

A rectangular coil (Dimension 5 cmxx2.5 cm ) with 100 turns, carrying a current of 3A in the origin and in the X-Z plane. A magnetic field of 1 T is applied along X-axis. If the coil is tilted through 45^(@) about Z-axis, then the torque on the coil is :