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Calculate the mean % error in five obser...

Calculate the mean % error in five observations :
`80.0,80.5,81.0,81.5,82`

A

`0.74%`

B

`1.74%`

C

`0.38%`

D

`1.38%`

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the mean percentage error in the given observations, we can follow these steps: ### Step 1: Calculate the Mean of the Observations The observations provided are: - 80.0 - 80.5 - 81.0 - 81.5 - 82.0 To find the mean, we sum all the observations and divide by the number of observations. \[ \text{Mean} = \frac{(80.0 + 80.5 + 81.0 + 81.5 + 82.0)}{5} \] Calculating the sum: \[ 80.0 + 80.5 + 81.0 + 81.5 + 82.0 = 405.0 \] Now, divide by 5: \[ \text{Mean} = \frac{405.0}{5} = 81.0 \] ### Step 2: Calculate the Deviations from the Mean Now, we will calculate the absolute deviations of each observation from the mean (81.0). 1. \( |80.0 - 81.0| = 1.0 \) 2. \( |80.5 - 81.0| = 0.5 \) 3. \( |81.0 - 81.0| = 0.0 \) 4. \( |81.5 - 81.0| = 0.5 \) 5. \( |82.0 - 81.0| = 1.0 \) ### Step 3: Sum of Absolute Deviations Now, we sum the absolute deviations calculated in Step 2: \[ \text{Total Deviation} = 1.0 + 0.5 + 0.0 + 0.5 + 1.0 = 3.0 \] ### Step 4: Calculate the Mean Absolute Deviation To find the mean absolute deviation, we divide the total deviation by the number of observations: \[ \text{Mean Absolute Deviation} = \frac{3.0}{5} = 0.6 \] ### Step 5: Calculate the Mean Percentage Error Finally, to find the mean percentage error, we use the formula: \[ \text{Mean Percentage Error} = \left( \frac{\text{Mean Absolute Deviation}}{\text{Mean}} \right) \times 100 \] Substituting the values we calculated: \[ \text{Mean Percentage Error} = \left( \frac{0.6}{81.0} \right) \times 100 \approx 0.7407\% \] Rounding to two decimal places, we get: \[ \text{Mean Percentage Error} \approx 0.74\% \] ### Final Answer The mean percentage error in the five observations is approximately **0.74%**. ---

To calculate the mean percentage error in the given observations, we can follow these steps: ### Step 1: Calculate the Mean of the Observations The observations provided are: - 80.0 - 80.5 - 81.0 - 81.5 ...
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