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Determine the pressure difference in tu...

Determine the pressure difference in tube of non-uniform cross sectional area as shown in figure `Delta P = ?`
`d_(1) = 5 cm, V_(1) = 4, d_(2) = 2 cm,V_(2) = ?`

A

a. 304200 Pa

B

b. 304500 Pa

C

c. 302500 Pa

D

d. 303500 Pa

Text Solution

Verified by Experts

The correct Answer is:
B
`A_(1)V_(1) = A_(2)V_(2)`
`5^(2) xx 4 = 2^(2) xx V_(2)`
`P_(1) + 1/2 + V_(1)^(2) = P_(2) + 1/2+ V_(2)^(2)`
`P_(1) - P_(2) = 1/2 + (V_(2)^(2) - V_(1)^(2))`
`= 1/2 xx 10^(3) (25^(2) - 4^(2))`
`= 500(625- 16)`
`P_(1) - P_(2) = 500xx609 = 304500 Pa`
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