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For the endothermic reactionA(2) hArr 2A...

For the endothermic reaction`A_(2) hArr 2A`, which of the following will increase yield of monomer?

A

Increase in both temperature and concentration of reactant

B

Increase in temperature and decrease in concentration of reactant.

C

Decrease in temperature and increase in concentration of reactant.

D

Decrease in both temperature and concentration of reactant.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the endothermic reaction \( A_2 \rightleftharpoons 2A \) and determine which condition will increase the yield of the monomer \( A \), we can follow these steps: ### Step-by-step Solution: 1. **Identify the Reaction**: The reaction given is \( A_2 \rightleftharpoons 2A \). Here, \( A_2 \) is the dimer (polymer) and \( A \) is the monomer. 2. **Determine the Nature of the Reaction**: The reaction is endothermic, which means it absorbs heat. In an endothermic reaction, heat can be considered a reactant. 3. **Apply Le Chatelier's Principle**: According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in concentration, temperature, or pressure, the equilibrium will shift in a direction that counteracts the change. 4. **Analyze Each Option**: - **Option 1**: Increase in both temperature and concentration of reactant. - Increasing concentration of \( A_2 \) will shift the equilibrium to the right (forward direction) to produce more \( A \). - Increasing temperature will also favor the endothermic reaction, shifting the equilibrium to the right. - **Conclusion**: This option will increase the yield of monomer \( A \). - **Option 2**: Increase in temperature and decrease in concentration of reactant. - Increasing temperature favors the forward reaction, but decreasing concentration of \( A_2 \) will shift the equilibrium to the left (backward direction). - **Conclusion**: This option will not increase the yield of monomer \( A \). - **Option 3**: Decrease in temperature and increase in concentration of reactant. - Decreasing temperature will favor the exothermic direction (backward reaction), while increasing concentration of \( A_2 \) will favor the forward reaction. - However, the decrease in temperature will dominate and shift the equilibrium to the left. - **Conclusion**: This option will not increase the yield of monomer \( A \). - **Option 4**: Decrease in both temperature and concentration of reactant. - Decreasing temperature will favor the backward reaction, and decreasing concentration of \( A_2 \) will also shift the equilibrium to the left. - **Conclusion**: This option will not increase the yield of monomer \( A \). 5. **Final Conclusion**: The only option that increases the yield of monomer \( A \) is **Option 1**: Increase in both temperature and concentration of reactant.
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