A train is travelling at a speed of `90 km//h`. Brakes are applied so as to produce a uniform acceleration of `- 0.5 m//s^(2)`. Find how far the train will go before it is brought to rest.

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of, -0.5 m/ s^(2) . How much distance will be covered by the scooter before it stops ?

Brakes are applied to a train travelling at 72 km//h . After passing over 200m , its velocity reduces to 36 km//h . At the same rate of retardation, how much further will it go before it is brought to rest ?

A train goes with a speed of 20 m/s what is the speed of train in km/h?

A train travelling at 90 km/h crosses a pole in 8 s. Find the length of the train (in m).

The brakes of a train which is travelling at 30 m//s are applied as the train passes point A. The brakes produce a constant retardation of magnitude 3lambda m//s^(2) until the speed of the train is reduced to 10 m//s . The train travels at this speed for a distance and is then uniformly accelerated at lambda m//s^(2) until it again reaches a speed of 30 m//s as it passes point B. the time taken by the train in travelling from A to B, a distance of 4 km, is 4 min. Sketch the speed time graph for this motion and calculate:- (i) The value of lambda (ii) Distance travelled at 10 m//s .