A racing car has a uniform acceleration of `4 m//s^(2)`. What distance will it cover in `10 s` after start ?

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of, -0.5 m/ s^(2) . How much distance will be covered by the scooter before it stops ?

The initial velocity of a body moving along a straight lines is 7m//s . It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

A body starting from rest and has uniform acceleration 8 m//s^(2) . The distance travelled by it in 5^(th) second will be

A particle, initially at rest, starts moving in a straight line with an acceleration a=6t+4 m//s^(2) . The distance covered by it in 3 s is

The radius of a wheel of car is 0.4m . The car is accelerated from rest by an angular acceleration of 1.5 rad//s^(2) for 20 s . How much distance will the wheel cover in this time and what will be its linear velaocity ?

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A drag racer, starting from rest, speeds up for 402 m with an acceleration of +17.0 m//s^(2) . A parachute then opens, slowing the car down with an acceleration of -6.10 m//s^(2) . How fast is the racer moving 3.50xx10^(2) m after the parachute opens ?

A car starts from rest and moves with uniform acceleration of 5 m//s^(2) for 8 sec. If the acceleration ceases after 8 seconds then find the distance covered in 12s starting from rest.