A stone is thrown in a vertically upward direction with a velocity of `5 m//s`. If the acceleration of the stone during its motion is `10 m//s^(2)` in the downward direction, what will be the height attained by the stone and how much time will take to reach there ?

A stone is thrown in a vertically upward direction with a velocity of 5ms-1.If the acceleration of the stone during its motion is 10ms-2 in the downward direction,what will be the height attained by the stone and how much time will it take to reach there?

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the time taken to reach the ground.

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the maximum height reached.

A stone of 200g is thrown vertically upward at a velocity of 60m/s. The kientic energy of the stone after 7s will be (g= 10m//s^(2))

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the time taken to reach the maximum height.

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

A stone is thrown horizontally with a velocity of 10 m//s at h = 0 . The radius of curvature of the stone's trajectory at t = 3s is : [Take g = 10 m//s^(2) ]

A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the acceleration of the stone be 9 .8 m//s^(2) directed towards the ground, calculate the initial velocity of the stone with which it apply Newton's third law to the gravitational force? explain your answer. on the distance between them. on the surface of the earth? is thrown upwards.