Find the value of 'g'.

"If "-(2)/(7),x,-(7)/(2)" are in G.P. Find the value of x."

Find the value of f(g(2#3)+g(f(1#2) :

If f(a, b)=(a+b)/(2) g(a, b)=a^(2)+b^(2) h(a, b)="max "(a, b) Find the value of f(g(3, 9)),h(-1, 1)

A students forgot the product rule for differentiation and made the mistake of thinking that (f.g)'=f'g'. However he was lucky to get the correct answer. The function f that he used was f(x) =e^(x^(2 If the domain of g(x) was the interval (1/2,oo)with g(1)=e. Find the value of g(5).

a#b=(-1)^(ab)(a^(b)+b^(a)) f(x)=x^(2)-2x if x ge 0 =0if x lt0 g(x)=2x, if x ge0 =1, if x lt0 Find the value of f(g(2#3))+g(f(1#2)):

The block is always at rest, the maximum force which can be applied for this is 24x. Find the value of x. Take g = 10 m//s^(2) {coefficient of friction = 0.3}

Find the value of a' if (2a+1),a,(3a+2) are in G.P?