The frequency of a tuning fork is 600 Hertz. What will be its time period ?

The frequency of a tuning fork is 600 Hz. What is the number of vibrations made by the tunning fork, when the sound produced by the tuning fork travels a distance of 110 ? (Velocity of sound in air is 330 ms^(-1) )

To reduce the frequency of a tuning fork –

The frequency of tuning fork is 256 Hz. It will not resonate with a fork of frequency

There is a source of sound (a tuning fork) moving towards a reflecting wall will a speed of 30 ms^(-1) . The velocity of the sound in air is 330 ms^(-1) and the frequency of the tuning fork is 600 Hz. The observer is between the source and the wall and is moving with some velocity V_(1) towards the wall. The beat frequency heard by the observer is 4 Hz. If the tuning fork is waxed, the frequency beats heard by the observer becomes 3 Hz. If the new frequency of tuning fork is k then k//50 is

An object is vibrating at 50 hertz. What is its time period?

A set of tuning forks is arranged in ascending order of frequency. Each tuning fork gives 5 beats per second with the preceding one. If the frequency of the first tuning fork is 100 Hz and that of last fork is 150 Hz, then the total number of tuning forks arranged are

The frequency of tuning fork A is 2% more than the frequency of a standard tuning fork. The frequency of a tuning fork B is 3% less than the frequency of the same standard tuning fork. If 6 beat/s are heard when the tuning fork A and B are excited , then frequency of A will be