Home
Class 12
CHEMISTRY
Hofmann mustard oil reaction....

Hofmann mustard oil reaction.

Text Solution

AI Generated Solution

### Step-by-Step Solution for Hofmann Mustard Oil Reaction **Step 1: Understanding the Reactants** - The Hofmann mustard oil reaction is primarily used to identify primary (1°), secondary (2°), and tertiary (3°) amines. The reaction involves a primary amine reacting with carbon disulfide (CS2) followed by mercuric chloride (HgCl2). **Step 2: Reaction of Primary Amine with CS2** - When a primary amine (R-NH2) reacts with carbon disulfide (CS2), the sulfur atom in CS2 acts as a nucleophile. The nitrogen atom of the amine donates a hydrogen atom to the sulfur, resulting in the formation of a thiourea intermediate. ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    ICSE|Exercise MULTIPLE CHOICE QUESTIONS (Assertion and Reason based questions)|10 Videos
  • SPECIMEN QUESTION PAPER

    ICSE|Exercise QUESTION|140 Videos

Similar Questions

Explore conceptually related problems

A compound (X) has the molecular formula C_3 H_7 NO . With Br_2 and KOH , (X) gives (Y) . (Y) responds to mustard oil reaction . (Y) upon treatment with HNO_2 evolves N_2 and gives an alcohol (Z) which gives iodoform test , (X) is likelty to be :

Which of the following undergoes mustard oil reaction ?

Hofmann elimination reaction.

Hofmann's Bromamide reaction

RCONH_2 is converted into RNH_2 by means of Hofmann bromamide degradation. In this RCONHBr is formed form which this reaction has derived its name. Electron-donating group at phenyl activities the reaction. Hofmann degradation reaction is an intramolecular reaction. Which is the rate-determining step in Hofmann bromamide degradation ?