Home
Class 12
CHEMISTRY
In a first order reaction, 10% of the re...

In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate :
The time required for completing 87.5% of the reaction.

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the principles of first-order kinetics. ### Step 1: Understand the Given Information We know that in a first-order reaction, 10% of the reactant A is consumed in 25 minutes. This means that 90% of A remains after 25 minutes. ### Step 2: Calculate the Rate Constant (k) For a first-order reaction, the rate constant \( k \) can be calculated using the equation: ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    ICSE|Exercise ISC EXAMINATION QUESTIONS (PART-II (DESCRIPTIVE QUESTIONS ) )|51 Videos
  • BIOMOLECULES

    ICSE|Exercise ISC EXAMINATION QUSTIONS (PART-I)(DESCRIPTIVE QUESTIONS)|21 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    ICSE|Exercise EXERCISE (PART - II (DESCRIPTIVE QUESTIONS) (LONG ANSWER QUESTIONS))|19 Videos

Similar Questions

Explore conceptually related problems

In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate : The time required for completing 17% of the reaction.

In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate : The time required for completing 17% of the reaction.

In a first order reaction, 10% of the reactant is consumed in 25 minuts. Calculate: The time required for complete 17% of the reaction.

In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate : The half-life of the reaction.

In a first order reaction, 10% of the reactant is consumed in 25 minuts. Calculate: The half life of the reaction.

In a first order reaction, 10% of the reactant is consumed in 25 minutes. Calculate : (1) The half-life period of the reaction. (2) The time required for completing 87.5% of the reaction.

ICSE-CHEMICAL KINETICS-ISC EXAMINATION QUESTIONS (NUMERICAL PROBLEMS )
  1. In a first order reaction, 10% of the reactant is consumed in 25 minut...

    Text Solution

    |

  2. In a first order reaction, 10% of the reactant is consumed in 25 minut...

    Text Solution

    |

  3. In a first order reaction, 10% of the reactant is consumed in 25 minut...

    Text Solution

    |

  4. If the half-life period for a first order reaction is 69.3 seconds, wh...

    Text Solution

    |

  5. The slope of the line in the graph of log k (k = rate constant) versus...

    Text Solution

    |

  6. A substance decomposes by following first order kinetics. If 50% of th...

    Text Solution

    |

  7. A first order reaction is 50% complete in 30 minutes at 27^@C. Calcula...

    Text Solution

    |

  8. The initial rate of a reaction A+B to Products is doubled when the co...

    Text Solution

    |

  9. Consider the reaction, A + B to C + D. The initial rate for differ...

    Text Solution

    |

  10. Consider the reaction, A + B to C + D. The initial rate for differ...

    Text Solution

    |

  11. Consider the reaction, A + B to C + D. The initial rate for differ...

    Text Solution

    |

  12. Consider the reaction, A + B to C + D. The initial rate for differ...

    Text Solution

    |

  13. Consider the reaction, A + B to C + D. The initial rate for differ...

    Text Solution

    |

  14. The rate constant of a first order reaction is 4.5 xx 10^(-2) sec^(-1)...

    Text Solution

    |

  15. 1g of strontium - 90 was reduced to 0.953 g after two years. Calculate...

    Text Solution

    |

  16. Show that the time required for the completion of 75% of a reaction of...

    Text Solution

    |

  17. A study of chemical kinetics of the reaction, A+B to Products, gave t...

    Text Solution

    |

  18. A study of chemical kinetics of the reaction, A+B to Products, gave t...

    Text Solution

    |

  19. A study of chemical kinetics of the reaction, A+B to Products, gave t...

    Text Solution

    |

  20. In a first order reaction, 10% of the reactant is consumed in 25 minut...

    Text Solution

    |