The slope of the line in the graph of log k (k = rate constant) versus `1/T `is - 5841. Calculate the activation energy of the reaction.

Explanation

To solve the problem of calculating the activation energy (Ea) from the slope of the line in the graph of log k versus 1/T, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship**: The relationship between the rate constant (k) and temperature (T) can be described by the Arrhenius equation in logarithmic form:
\[ \log k = \log A - \frac{E_a}{2.303R} \cdot \frac{1}{T} \]
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