In the extraction of copper from its sulfide ore, the metal is formed by the reduction of `Cu_2O` with

Options

A. `FeS`
B. `CO`
C. `Cu_2S`
D. `SO_2`

Explanation

To solve the question about the extraction of copper from its sulfide ore, we need to break down the process step-by-step.

### Step-by-Step Solution:

1. **Identify the Ore**: The primary ore of copper is copper pyrite, which is chemically represented as \( \text{CuFeS}_2 \).

2. **Roasting of the Ore**: The first step in the extraction process is roasting the copper pyrite in the presence of oxygen. This process converts the sulfide ore into copper(I) sulfide (\( \text{Cu}_2\text{S} \)), iron(II) sulfide (\( \text{FeS} \)), and sulfur dioxide (\( \text{SO}_2 \)). The reaction can be represented as:
\[ 2 \text{CuFeS}_2 + 5 \text{O}_2 \rightarrow 2 \text{Cu}_2\text{S} + 2 \text{FeS} + 4 \text{SO}_2 \]

3. **Formation of Copper Oxide**: During the roasting process, some of the copper(I) sulfide (\( \text{Cu}_2\text{S} \)) can be further oxidized to copper(I) oxide (\( \text{Cu}_2\text{O} \)).

4. **Reduction of Copper Oxide**: The question specifically asks about the reduction of \( \text{Cu}_2\text{O} \). In the presence of iron sulfide (\( \text{FeS} \)), \( \text{Cu}_2\text{O} \) can be reduced to form copper sulfide (\( \text{Cu}_2\text{S} \)) and iron(II) oxide (\( \text{FeO} \)). The reaction is as follows:
\[ \text{Cu}_2\text{O} + \text{FeS} \rightarrow \text{Cu}_2\text{S} + \text{FeO} \]

5. **Final Products**: The overall process results in the formation of copper sulfide (\( \text{Cu}_2\text{S} \)) and iron oxide (\( \text{FeO} \)) from the reduction of copper oxide (\( \text{Cu}_2\text{O} \)).

### Conclusion:
The metal copper is formed by the reduction of \( \text{Cu}_2\text{O} \) with iron sulfide (\( \text{FeS} \)).