The compound oxidised to prepare methyl ethyl ketone is

Options

A. 2-Propanol
B. 1-Butanol
C. 2-Butanol
D. t-Butyl alcohol.

Explanation

To determine the compound that is oxidized to prepare methyl ethyl ketone (MEK), we need to identify the appropriate alcohol that, upon oxidation, yields MEK. Here’s the step-by-step solution:

### Step 1: Understand the structure of Methyl Ethyl Ketone
Methyl ethyl ketone (MEK) has the following structure:
- It is a ketone with the formula C4H8O.
- The structure can be represented as CH3COC2H5, where one side has a methyl group (CH3) and the other side has an ethyl group (C2H5).

### Step 2: Identify potential alcohols that can be oxidized
We will consider common alcohols that could potentially be oxidized to form MEK:
1. 2-Propanol (isopropanol)
2. 1-Butanol
3. 2-Butanol

### Step 3: Analyze each alcohol for oxidation
- **2-Propanol**:
- Structure: CH3CHOHCH3
- Upon oxidation, it converts to acetone (CH3COCH3), which does not have the ethyl group, so this is not the correct answer.

- **1-Butanol**:
- Structure: CH3CH2CH2CHOH
- Upon oxidation, it converts to butanal (an aldehyde), which also does not yield a ketone. Therefore, this is not the correct answer.

- **2-Butanol**:
- Structure: CH3CH(OH)CH2CH3
- Upon oxidation, it converts to methyl ethyl ketone (CH3COC2H5), which matches our target compound. Hence, this is the correct answer.

### Conclusion
The compound oxidized to prepare methyl ethyl ketone is **2-butanol**.

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