Compound `Ph-O-overset(O)overset(||)C-Ph` can be prepared by the reaction of

Options

A. Phenol and benzoic acid in the presence of NaOH
B. Phenol and benzoyl chloride in the presence of pyridine
C. Phenol and benzoyl chloride in the presence of `ZnCl_(2)`
D. Phenol and benzaldehyde in the presence of palladium.

Answer

To prepare the compound `Ph-O-C(=O)-Ph`, which is an ester, we can follow these steps:

### Step 1: Identify the Reactants
The compound consists of a phenyl group (Ph) attached to an oxygen atom, which is then connected to a carbonyl group (C=O) and another phenyl group. This indicates that the compound is an ester formed from phenol and benzoic acid.

### Step 2: Write the Reaction
The reaction involves the esterification process between phenol (C6H5OH) and benzoic acid (C6H5COOH). The general reaction for ester formation can be represented as:
\[ \text{Phenol} + \text{Benzoic Acid} \rightarrow \text{Ester} + \text{Water} \]

### Step 3: Mechanism of Esterification
1. **Protonation of the Alcohol**: In an acidic medium, the hydroxyl group of phenol can be protonated to form a better leaving group.
2. **Nucleophilic Attack**: The phenol (now protonated) acts as a nucleophile and attacks the carbonyl carbon of benzoic acid.
3. **Formation of Tetrahedral Intermediate**: This leads to the formation of a tetrahedral intermediate.
4. **Elimination of Water**: The tetrahedral intermediate collapses, leading to the elimination of water and the formation of the ester.

### Step 4: Final Product
The final product of this reaction is the ester `Ph-O-C(=O)-Ph` (phenyl benzoate) along with the release of water.

### Conclusion
Thus, the compound `Ph-O-C(=O)-Ph` can be prepared by the reaction of phenol and benzoic acid in the presence of an acidic medium or basic medium.

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