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The velocity constant of a reaction at 2...

The velocity constant of a reaction at 290 K was found to be `3.2 xx 10^(-3) s^(-1)`. When the temperature is raised to 310 K, it will be about

A

`6.4 xx 10^(-3)`

B

`3.2 xx 10^(-4)`

C

`9.6 xx 10^(-3)`

D

`1.28 xx 10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
For each `10^@` rise in temperature, reaction rate get doubled.
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